A) \[s{{p}^{3}}\]
B) \[s{{p}^{2}}\]
C) \[sp\]
D) \[s{{p}^{3}}d\]
Correct Answer: A
Solution :
Word hypo reveals that in it I is in + 1 oxidation state, ie, it is iodous (I) acid or \[HOI\]. In \[HOI\], number of hybrid orbitals \[=\frac{1}{2}[7+1-0+0]=4\] \[\therefore \] In it, iodine atom uses sp3 hybrid orbitals.
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