AIIMS AIIMS Solved Paper-2010

  • question_answer
    Consider the sequence of oxides: \[N{{a}_{2}}O,Si{{O}_{2}},\] \[{{P}_{4}}{{O}_{10}}.\]. Which factor decreases from \[N{{a}_{2}}O\] to \[Si{{O}_{2}}\] and also from \[Si{{O}_{2}}\] to \[{{P}_{4}}{{O}_{10}}\]?

    A) Covalent character

    B) Melting point

    C) pH when mixed with water

    D) Solubility in aqueous alkali

    Correct Answer: C

    Solution :

    \[N{{a}_{2}}O\] is a basic oxide and reacts with water to give \[NaOH\] so that its pH is higher than both \[Si{{O}_{2}}\] and \[{{P}_{4}}{{O}_{10}}\]. Both \[Si{{O}_{2}}\] and \[{{P}_{4}}{{O}_{10}}\] are acidic oxides but \[Si{{O}_{2}}\] is insoluble while \[{{P}_{4}}{{O}_{10}}\] reacts with water to give \[{{H}_{3}}P{{O}_{4}}\]. Thus, for \[{{P}_{4}}{{O}_{10}}\], pH when mixed with water is lower than that of \[Si{{O}_{2}}\].


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