A) 11 g
B) 22 g
C) 33 g
D) 44 g
Correct Answer: B
Solution :
van der Waals gas equation for a mole of real gas \[\frac{\Delta Q}{\Delta T}=200kcal/h\] \[=\frac{200\times 1000\times 4.2}{60\times 60}J/s\] Given equation, \[=233.33J/s\] On comparing the given equation with this standard equation, we get \[A=5c{{m}^{2}}=5\times {{10}^{-4}}{{m}^{2}}\] Hence, \[A=5c{{m}^{2}}=5\times {{10}^{-4}}{{m}^{2}}\] \[\therefore \] mass of gas \[K=\frac{\Delta Q/\Delta T}{A(\Delta T/\Delta x)}\]
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