AIIMS AIIMS Solved Paper-2010

  • question_answer
    A capacitor of capacitance \[\frac{2}{5}\] is charged to a potential of 1 V. It is connected in parallel to an inductor of inductance 10-3 H. The maximum current that will flow in the circuit has the value

    A)  \[\frac{3}{5}\]                                  

    B)  1 A                        

    C)         1 mA                    

    D)         1000 mA

    Correct Answer: A

    Solution :

    Change on the capacitor, \[Mg\frac{d}{4}\] Here, \[3Mg\frac{d}{4}\] or  \[-3Mg\frac{d}{4}\]  maximum current Now, \[l\] \[2l\] \[\frac{l}{2}\] \[4l\]


You need to login to perform this action.
You will be redirected in 3 sec spinner