A) \[=\frac{\sqrt{gh}/2}{g}\left[ 1+\sqrt{1+\frac{2gh}{gh/4}} \right]\]
B) \[=\frac{2\sqrt{gh}}{g}=2\sqrt{\frac{h}{g}}\]
C) \[=\frac{M{{R}^{2}}}{2}\]
D) \[=M\left( \frac{{{L}^{2}}}{I2}+\frac{{{L}^{2}}}{4} \right)\]
Correct Answer: B
Solution :
The velocity of balloon at height h \[\overset{0}{\mathop{A}}\,\] When the stone released from this balloon. It will go upward with velocity \[1.33\times {{10}^{11}}N/{{m}^{2}}\] In this condition time taken by stone to reach the ground \[1.33\times {{10}^{12}}N/{{m}^{2}}\] \[7.5\times {{10}^{-13}}N/{{m}^{2}}\] \[3\times {{10}^{10}}N/{{m}^{2}}\]
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