AIIMS AIIMS Solved Paper-2010

  • question_answer
    A thin magnetic needle vibrates in the horizontal plane with a period of 4 s. The needle is cut into two halves by a plane normal to magnetic axis of the needle. Then the period of vibration of each half needle is approximately

    A)  4s                                          

    B)  2s                          

    C)         8s                          

    D)         1 s

    Correct Answer: B

    Solution :

    The moment of inertia of needle when it cuts into two halves by a plane normal to magnetic axis of the needle. \[I\,=\frac{1}{12}\,\left( \frac{m}{2} \right)\,{{\left( \frac{l}{2} \right)}^{2}}\,\]      or    \[g\propto \frac{1}{{{(R+h)}^{2}}}\] Also,      \[\therefore \] \[g=g\frac{{{R}^{2}}}{{{(R+h)}^{2}}}=\frac{9.8\times {{(6400)}^{2}}}{{{(6400+480)}^{2}}}\] The period of vibration \[=8.4m/{{s}^{2}}\] \[\left( P+\frac{{{\mu }^{2}}a}{{{V}^{2}}} \right)(V-\mu b)=\mu RT\]


You need to login to perform this action.
You will be redirected in 3 sec spinner