A) A only
B) A and B
C) All of these
D) None of these
Correct Answer: B
Solution :
Work function for wavelength of \[\frac{1}{86400}{{/}^{0}}C\] is \[\frac{1}{43200}{{/}^{0}}C\] \[\frac{1}{44400}{{/}^{0}}C\] \[\frac{1}{28800}{{/}^{0}}C\] \[9\times {{10}^{-1}}C\] Now, we have \[{{R}_{2}}=\frac{{{V}^{2}}}{{{P}_{2}}}=\frac{{{(220)}^{2}}}{100}484\Omega \] Since, \[{{C}_{4}}=4C\] and \[{{C}_{2}}\], hence, A and B will emit photoelectrons.
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