A) \[4.85\text{ }g/cc\]
B) \[4.85\text{ }g/cc\]
C) \[A(g)+B(g)\rightleftharpoons C(g)+D(g)\]
D) \[4.5\]
Correct Answer: B
Solution :
Species having the same number of unpaired electrons, have same magnetic moment. \[[O{{H}^{-}}]=\frac{1\times {{10}^{-14}}}{1\times {{10}^{-10}}}=1\times {{10}^{-4}}mol/L\] (five unpaired electrons) \[\because \] (one unpaired electron) \[1\text{ }mol=\text{ }6.023\times {{10}^{23}}\] (one unpaired electron) \[\therefore \] (one unpaired electron) \[\because \] \[=6.023\times {{10}^{19}}\] and \[\therefore \] have same magnetic moment. \[=\frac{6.023\times {{10}^{19}}\times 100}{1000}\] \[=6.023\times {{10}^{18}}.\] (no unpaired electron) \[C{{H}_{4}}+2{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}+2{{H}_{2}}O;\] (two unpaired electrons) \[\Delta =210kcal/mol\] (one unpaired electron) \[{{C}_{2}}{{H}_{6}}+\frac{7}{2}{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}}+3{{H}_{2}}O;\] (two unpaired electron)
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