A) \[N{{a}_{2}}{{B}_{4}}{{O}_{7}}\xrightarrow{{{740}^{o}}C}2\underbrace{2\underset{\begin{smallmatrix} sodium \\ metaborate \end{smallmatrix}}{\mathop{NaB{{O}_{2}}}}\,+\underset{\begin{smallmatrix} boric \\ anhydride \end{smallmatrix}}{\mathop{{{B}_{2}}{{O}_{3}}}}\,}_{glassy\,\,bead}\]
B) \[W=\frac{EN\,V}{1000}\]
C) \[N=\frac{1.575\times 1000}{63\times 250}\]
D) \[\because \]
Correct Answer: C
Solution :
Diethylamine is a weak base and from Ostwalds dilution law, for weak base, \[\therefore \] \[a=395.6pm\] \[=\frac{ZM}{{{N}_{a}}a}\] \[d=\frac{2\times 23}{6.023\times {{10}^{23}}\times {{(3.956)}^{3}}\times {{10}^{-24}}}\] \[=1.23g/cc.\] \[(HN{{O}_{3}})\] \[(NO),N{{O}_{2}}\] \[{{H}_{2}}S\] \[2HN{{O}_{3}}+NO\xrightarrow{{}}{{H}_{2}}O+3N{{O}_{2}}\]
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