A) \[+1,\,+3,\,+7\]
B) \[T{{i}^{3+}}=[Ar]3{{d}^{1}}\]
C) \[FeC{{l}_{3}}\]
D) \[F{{e}^{3+}}=[Ar]3{{d}^{5}}\]
Correct Answer: C
Solution :
Oxidation state of I in \[Zn|ZnS{{O}_{4}}\,(0.01M)||CuS{{O}_{4}}(1.0M)|Cu\] is \[ZnS{{O}_{4}}\] as: \[CuS{{O}_{4}}\] \[{{E}_{2}}\] Oxidation state of l in \[{{E}_{1}}\], is \[{{E}_{2}}\] as. \[{{E}_{1}}={{E}_{2}}\] \[{{E}_{2}}=0\ne {{E}_{2}}\] Oxidation state of I in \[{{E}_{1}}>{{E}_{2}}\] is \[{{E}_{1}}<{{E}_{2}}\]as \[0.02\text{ }m{{s}^{-1}}\] \[\left( \frac{\Delta {{x}_{A}}}{\Delta {{x}_{B}}} \right)\]
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