A) \[{{H}_{2}}S\]
B) \[S{{O}_{3}}\]
C) \[{{H}_{2}}{{O}_{2}}\]
D) \[{{F}_{2}}\]
Correct Answer: B
Solution :
For a reaction, \[C{{H}_{2}}=C(C{{H}_{3}})C{{H}_{2}}C{{H}_{2}}Br\] Hence, if \[C{{H}_{3}}-C(C{{H}_{3}})=CHC{{H}_{2}}-Br\], then [Product] > [Reactant]
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