A) \[{{E}_{2}}\]
B) \[{{E}_{1}}\]
C) \[{{E}_{2}}\]
D) \[{{E}_{1}}={{E}_{2}}\]
Correct Answer: A
Solution :
It is Stephens reaction. \[{{(C{{H}_{3}})}_{3}}N\] \[C{{H}_{3}}OH+HO-C{{H}_{2}}-C{{H}_{3}}\xrightarrow{conc.\,{{H}_{2}}S{{O}_{4}}}\] \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-Br+C{{H}_{3}}OH\xrightarrow{H{{O}^{-}}N{{a}^{+}}}\]
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