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AIIMS AIIMS Solved Paper-2008

  • question_answer
    A radioactive material decays by simultaneous emission of two particles with respective half lives 1620 yr and 810 yr. The time (in years) after which one-fourth of the material remains is

    A)  1080  

    B)                                        2430                     

    C)        3240                     

    D)        4860

    Correct Answer: A

    Solution :

    \[\pi /\omega \] \[2\pi /\omega \]   \[\pi /\omega \] \[\frac{4}{3}\]  \[36\sqrt{7}\] Hence, \[\frac{36}{\sqrt{7}}\] of material remain after 1080 yr.


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