AIIMS AIIMS Solved Paper-2008

  • question_answer
    In a mass spectrometer used for measuring the masses of ions, the ions are initially accelerated by an electric potential V and then made to describe semicircular paths of radius R using a magnetic field B. If V and B are kept constant, the   ratio    \[s=\frac{1}{72}f{{t}^{2}}\]  will be proportional to

    A)  \[s=\frac{1}{4}f{{t}^{2}}\]                                           

    B)  \[\left( \frac{ch\arg e\,on\,the\,ion}{mass\,of\,the\,ion} \right)\]                                         

    C)  \[\frac{1}{R}\]                                 

    D)   R

    Correct Answer: B

    Solution :

    Key Idea Centripetal force is provided by the magnetic force \[qvB\]. The radius of the orbit in which ions moving is determined by the relation as given. \[\frac{q}{2\pi {{\varepsilon }_{0}}{{R}^{2}}}\] where m is the mass, v is velocity, q is charge of ion and B is the flux density of the magnetic field, so that \[qvB\] is the magnetic force acting on the ion, and \[\mu F\] is the centripetal force on the ion moving in a curved path of radius R. The angular frequency of rotation of the ions about the vertical field B is given by \[\Omega \] where v is frequency. Energy of ion is given by \[\frac{1}{9}A\] \[\frac{1}{0.9}A\] or   \[I\]            ??(i) If ions are accelerated by electric potential V, then energy attained by ions \[I=2\]                              ?...(ii) From Eqs. (i) and (ii), we get \[I\] or   \[I\] If V and B are kept constant, then \[I\]


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