question_answer

A parachutist after bailing out falls SO m without friction. When parachute opens, it decelearates at \[2\,m/{{s}^{2}}\]. He reaches the ground with a speed of 3 m/s. At what height, did he bail out?

A)  91 m                                    

B)  182 m                                  

C)  293m                                   

D)  111m

Correct Answer: C

Solution :

Parachute bails out at height H from ground. Velocity at A                 \[\alpha \]                 \[\Omega \] \[\Omega \] The velocity at ground \[\Omega \]     (given) Acceleration    \[\Omega \]           (given) \[\sqrt{50}\]   \[\sqrt{5}\] \[\sqrt{52}\] \[\sqrt{52}\] \[\sqrt{5}\]  \[{{G}^{1/2}}{{h}^{1/2}}{{c}^{-5/2}}\] \[{{G}^{-1/2}}{{h}^{1/2}}{{c}^{1/2}}\]