A) \[NaOH\]
B) \[\beta \]
C) \[C{{H}_{3}}CHO+C{{H}_{3}}CHO\xrightarrow{NaOH}\underset{3-hydroxy\,bu\tan al}{\mathop{C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO}}\,\]
D) \[{{\text{K}}_{\text{c}}}\text{=}\frac{\text{ }\!\![\!\!\text{ Product }\!\!]\!\!\text{ }}{\text{ }\!\![\!\!\text{ Reactant }\!\!]\!\!\text{ }}\]
Correct Answer: C
Solution :
Hydrogen peroxide \[{{T}_{50}}\] can act as an oxidizing as well as a reducing agent. \[10mol\,{{L}^{-1}}\]as an reducing agent: \[0.0693\,mol\,{{L}^{-1}},\,{{\min }^{-1}}\] \[0.0693\times 2.5\,mol\,{{L}^{-1}}\,{{\min }^{-1}}\] as a oxidizing agent: \[0.0693\times 5\,mol\,{{L}^{-2}}\,{{\min }^{-1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
