AIIMS AIIMS Solved Paper-2007

  • question_answer
    Two radioactive substances A and B have decay constants 5\[\mu k\] and \[\mu k\] respectively. At t = 0 they have the same number of nuclei. The ratio of number of nuclei of A to those of B will be \[{{\left( \frac{1}{e} \right)}^{2}}\] after a time interval

    A)  \[\mu k\]           

    B)                        \[^{40}Ar\]                       

    C)  \[^{40}k\]                          

    D)        \[2.95\times {{10}^{11}}yr\]

    Correct Answer: D

    Solution :

    Number of nuclei remained after time t can be written as \[\pi \] where \[\pi \] is initial number of nuclei of both the substances. \[\pi \]                            ?.....(i) and     \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-1}}]\]                   ?...(ii) Dividing Eq. (i) by Eq. (ii), we obtain \[[M{{L}^{2}}{{T}^{-2}}]\] But, we have given \[[M{{L}^{2}}{{T}^{-1}}{{I}^{-1}}]\] Hence,   \[[M{{L}^{2}}{{T}^{-3}}{{I}^{-2}}]\]       Comparing the powers, we get \[\frac{pV}{nT}\] or         \[{{T}_{1}}>{{T}_{2}}\]


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