A) 723 kJ
B) 924 kJ
C) 482 kJ
D) 241 kJ
Correct Answer: C
Solution :
\[C{{H}_{3}}OH(l)+\frac{3}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)+2{{H}_{2}}O(l)\] \[\Delta H=-732kJ\] By burning with \[\frac{3}{2}{{O}_{2}}(g)\]heat evolved \[=-723kJ\] \[\therefore \]By burning with 1 mole \[{{O}_{2}}(g)=\frac{-732\times 2}{3}\] \[=-482kJ\]You need to login to perform this action.
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