A) \[\log \,k\,vs\,T\]
B) \[\log \,k\,vs\,\frac{1}{T}\]
C) \[k\,\,vs\,\,\,T\]
D) \[k\,\,vs\,\,\,\frac{1}{\log T}\]
Correct Answer: B
Solution :
\[k=A{{e}^{-{{E}_{a}}/RT}}\] \[\log k=\log A-\frac{{{E}_{a}}}{2.303RT}\] Comparing this equation with straight line \[y=mx+c\] \[y=\log k\] and \[x=\frac{1}{T}\]. \[\therefore \]\[{{E}_{a}}\] is calculated with the help of slope by plotting the curve between log k and \[\frac{l}{T}\].You need to login to perform this action.
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