A)
B)
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Correct Answer: B
Solution :
According to law of Malus, when a beam of completely plane polarised light is incident on an analyser, the resultant intensity of light \[\mu k\] transmitted from the analyser varies directly as the square of the cosine of the angle \[^{40}Ar\] between planes of transmission of analyser and polariser. ie, \[^{40}k\] and \[2.95\times {{10}^{11}}yr\] ??.(i) where \[2.95\times {{10}^{9}}yr\] = intensity of the light from polariser. From Eq. (i), we note that if the transmission axes of polariser and analyser are parallel (ie, \[4.37\times {{10}^{9}}yr\] or \[4.37\times {{10}^{11}}yr\]), then \[\sigma \] means that intensity of transmitted light is maximum. When the transmission axes of polariser and analyser are perpendicular (ie, \[\rho \]), then \[\lambda \]. It means the intensity of transmitted light is minimum. On plotting a graph between \[I\] and \[\theta \] as given by relation (i), we get the curve as shown in figure.You need to login to perform this action.
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