A) \[{{C}_{6}}{{H}_{5}}N=N-{{C}_{6}}{{H}_{5}}\]
B) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}NO\]
D) \[{{C}_{6}}{{H}_{5}}NHOH\]
Correct Answer: D
Solution :
When nitrobenzene is reduced with a neutral reducing agent (\[Zn\] dust \[+N{{H}_{4}}Cl,\,\,Al-Hg\] couple and water), pheylhydroxylamine is formed. \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+2[H]\xrightarrow[+N{{H}_{4}}Cl-{{H}_{2}}O]{Zn\,\,dust}\underset{Nitrosobenzene}{\mathop{{{C}_{6}}{{H}_{5}}NO}}\,\] \[\xrightarrow{2[H]}\underset{Phenyl\,hydroxyla\min e}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,\]
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