A) <124kV
B) >124Kv
C) Between 60 kV and 70 RV
D) = 100 kV
Correct Answer: A
Solution :
From conservation of energy the electron kinetic energy equals the maximum photon energy (we neglect the work function \[\phi \] because it is normally so small compared to \[e{{V}_{0}})\]. \[e{{V}_{0}}=h{{v}_{\max }}\] or \[e{{V}_{0}}=\frac{hv}{{{\lambda }_{\min }}}\] \[\therefore \] \[{{V}_{0}}=\frac{hc}{e{{\lambda }_{\min }}}\] or \[{{V}_{0}}=\frac{12400\times {{10}^{-10}}}{{{10}^{-11}}}=124kV\] Hence, accelerating voltage for electrons in X-ray machine should be less than 124 kV.
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