A) \[\Delta G=0\]
B) \[\Delta S=0\]
C) \[\Delta H=0\]
D) \[\Delta U=0\]
Correct Answer: A
Solution :
\[{{H}_{2}}O(l){{H}_{2}}O(s)\] for equilibrium at constant pressure and temperature. \[G=A+PV\] \[dG=dA+PdV+VdP\] At constant T and P we obtain \[{{(\partial G)}_{T,P}}=0\] for infinitesimal change \[{{(\Delta G)}_{T.P}}>0\] So, at equilibrium \[\Delta G=0\]
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