AIIMS AIIMS Solved Paper-2006

  • question_answer
    For the reaction \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\] rate of reaction is:

    A)  \[\frac{1}{2}\frac{d}{dt}[{{N}_{2}}{{O}_{5}}]\]                  

    B)  \[2\frac{d}{dt}[{{N}_{2}}{{O}_{5}}]\]     

    C)         \[\frac{1}{4}\frac{d}{dt}[N{{O}_{2}}]\]    

    D)         \[4\frac{d}{dt}[N{{O}_{2}}]\]

    Correct Answer: C

    Solution :

    \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\] rate of reaction is: \[\frac{1}{2}\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}=\frac{1}{4}\frac{d[N{{O}_{2}}]}{dt}\] So, rate of disappearance of \[{{N}_{2}}{{O}_{5}}\]  is represented either by \[-\frac{1}{2}\frac{[{{N}_{2}}{{O}_{5}}]}{dt}\] or by \[\frac{1}{4}\frac{d[N{{O}_{2}}]}{dt}\]


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