A) tetrahedral voids
B) half of tetrahedral voids
C) octahedral voids
D) half of octahedral voids
Correct Answer: A
Solution :
In \[Ca{{F}_{2}}\] radius ratio =0.73 It suggested its crystal structure to be body centered cubic. In this each \[C{{a}^{2+}}\] ion is surrounded by eight \[{{F}^{-}}\] ions, i.e., co-ordination number is eight and for fluorine it is 4. In fluorite the \[C{{a}^{2+}}\] ions are too small to touch each other, hence the structure is not strictly close packed structure relative positions of \[C{{a}^{2+}}\] ions are like ions in a cubic close packed structure in which all the tetrahedral holes are occupied by the \[{{F}^{-}}\] ions.
You need to login to perform this action.
You will be redirected in
3 sec
