A) \[6.626\times {{10}^{-34}}m\]
B) \[13.20\times {{10}^{-34}}m\]
C) \[10.38\times {{10}^{-21}}m\]
D) \[6.626\times {{10}^{-34}}\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: A
Solution :
\[\lambda =\frac{h}{\sqrt{2m(KE)}}\] \[=\frac{6.626\times {{10}^{-34}}}{\sqrt{2\times 1\times 0.5}}=\frac{6.626\times {{10}^{-34}}}{\sqrt{1\times 1}}\] \[=6.626\times {{10}^{-34}}m\]
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