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AIIMS AIIMS Solved Paper-2006

  • question_answer
    In \[{{[Ag{{(CN)}_{2}}]}^{2-}}\], the number of \[\pi \] bonds is:

    A)  \[2\]

    B)                                         \[3\]                    

    C)  \[4\]                    

    D)         \[6\]

    Correct Answer: C

    Solution :

    In \[Ag{{[{{(CN)}_{2}}]}^{2-}},\,\,C{{N}^{-}}\] has \[\pi \] bonds \[C\equiv N\] so two \[\pi \] -bonds are present in one CN so, the number of \[\pi \] bonds are \[2\times 2=4\].


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