question_answer

The number of possible isomers of an octahedral complex \[{{[Co{{({{C}_{2}}{{O}_{4}})}_{2}}{{(N{{H}_{3}})}_{2}}]}^{-}}\] is:

A)  1          

B)                         2                            

C)  3                            

D)         4

Correct Answer: C

Solution :

\[[Co{{({{C}_{2}}{{O}_{4}})}_{2}}{{(N{{H}_{3}})}_{2}}]\] has 3 isomers  (1) C is-isomer                   (2) Trans-isomer It forms two optically isomeric forms