A) 40 \[k\Omega \]
B) 4k\[k\Omega \]
C) 200\[k\Omega \]
D) 400\[k\Omega \]
Correct Answer: D
Solution :
The term LED is abbreviated as Light Emitting Diode. It is forward-biased p-n junction which emits spontaneous radiation. Current in the circuit \[=10m\,A=10\times {{10}^{-3}}A\] and voltage in the circuit \[=6-2=4V\] From Ohms law. \[V=IR\] \[\therefore \] \[R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\Omega \]
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