Direction for: In each of the following questions a statement of Assertion is given followed by a corresponding statement of Reason just below it. Of the statements mark the correct answer as
Assertion: For the Daniel cell \[Zn|Z{{n}^{2+}}||C{{u}^{2+}}|.Cu\] with \[{{E}_{cell}}=1.1V,\] the application of opposite potential greater than 1.1 V results into flow of electron from cathode to anode. Reason: \[Zn\] is deposited at anode and \[Cu\] is deposited at cathode.A) If both assertion and reason are true and the reason is the correct explanation of the assertion.
B) If both assertion and reason are true but the reason is not the correct explanation of the assertion.
C) If assertion is true statement but reason is false.
D) If both assertion and reason are false.
Correct Answer: A
Solution :
In a Daniel cell \[Zn|Z{{n}^{2+}}||C{{u}^{2+}}|Cu\] \[{{E}_{cell}}=1.1V\] The reaction of oxidation half cell \[Zn\xrightarrow{{}}Z{{n}^{2+}}+2{{e}^{-}}\] The reaction of reduction half cell \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Cu\] So, \[Zn+C{{u}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Cu\] because \[Zn\] is oxidised, it is deposited at anode and \[Cu\] is reduced so, it is deposited at cathode. If the opposite potential is greater than\[1.1V\], then the electrons flow from cathode to anode. So both the statements are true and correct explanation.
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