A) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}CH(Br)C{{H}_{3}}\]
B) \[{{C}_{6}}{{H}_{5}}CH(Br)C{{H}_{2}}C{{H}_{3}}\]
C) \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OC{{H}_{3}}\]
Correct Answer: A
Solution :
The auction of \[HBr\] on unsymmetrical alkene take place on the basis of Markownikoffs addition?The negative part of the addendum is added to that carbon atom which has lesser number of H atoms. \[\underset{3-phenlypropene}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}-CH=C{{H}_{2}}+\overset{+}{\mathop{H}}\,\overset{-}{\mathop{B}}\,r\xrightarrow{{}}}}\,\] \[\underset{2-bromo-3-phenyl\,propane}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}\overset{Br}{\mathop{\overset{|}{\mathop{CH}}\,}}\,C{{H}_{3}}}}\,\]
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