A) \[-0.1\left[ \frac{{{(30)}^{2}}}{2}-\frac{{{(20)}^{2}}}{2} \right]={{K}_{f}}-500\]
B) \[\Rightarrow \]
C) \[{{K}_{f}}-500=-25\]
D) \[\Rightarrow \]
Correct Answer: C
Solution :
A black hole is an object so massive that even light cannot escape from it. This requires the idea of a gravitational mass for a photon, which then allows the calculation of an escape energy, for an object of that mass. When gravitational potential energy of the photon is exactly equal to the photon energy, then \[2\sigma /{{\varepsilon }_{0}}V/m\] ??(1) where G is gravitational constant, M is mass, r is radius, c is speed of light, h is Plancks constant. Then from Eq. (1) we have \[{{\mu }_{e}}\] Note that this condition is independent of frequency v. Schwarz childs calculated gravitational radius differs from this result by a factor of 2 and is coincidently equal to the non-relativistic escape velocity expression. \[{{\mu }_{h}}\]
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