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AIIMS AIIMS Solved Paper-2005

  • question_answer
    \[_{92}^{238}U\] emits 8 \[\alpha \]-particles and \[6\beta \]-particles. The neutron/proton ratio in the product nucleus is:

    A) \[60/41\]            

    B)        \[61/40\]            

    C)        \[62/41\]         

    D)        \[61/42\]

    Correct Answer: C

    Solution :

    \[_{92}{{U}^{238}}{{\xrightarrow{-8\alpha }}_{76}}{{X}^{206}}{{\xrightarrow{-6\beta }}_{82}}{{Y}^{206}}\] In Y, number of protons = 82 number of neutrons = mass number - number of proton \[=206-82\] \[=124\] \[\frac{n}{p}=\frac{124}{82}=\frac{62}{41}\]


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