Among the following molecules (i) \[\overset{\centerdot \centerdot }{\mathop{X}}\,e{{O}_{3}}\] (ii) \[\overset{\centerdot \centerdot }{\mathop{X}}\,eO{{F}_{4}}\] (iii) \[\overset{\centerdot \centerdot }{\mathop{X}}\,e{{F}_{6}}\] Those having same number of lone pairs on \[Xe\] are:
A)(i) and (ii) only
B)(i) and (iii) only
C)(ii) and (iii) only
D)(i), (ii) and (iii)
Correct Answer:
D
Solution :
\[XeO{{F}_{4}}\]. square planar {\[s{{p}^{3}}{{a}^{2}}\] hybridization) As shown above all the compounds have one lone pair.