A) \[[Co{{({{H}_{2}}O)}_{4}}C{{l}_{2}}]\]
B) \[{{[Co{{({{H}_{2}}O)}_{2}}C{{l}_{4}}]}^{2-}}\]
C) \[{{[CoC{{l}_{4}}]}^{2-}}\]
D) \[[Co{{({{H}_{2}}O)}_{2}}C{{l}_{2}}]\]
Correct Answer: C
Solution :
\[CoC{{l}_{2}}\] is weak Lewis. It reacts with chloride ion to produce salt containing the tetrahedral \[{{[CoC{{l}_{4}}]}^{2-}}\] ion which is blue in colour. The oxidation state of \[Co\] is \[+2\].
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