question_answer

Among the following molecules (i) \[\overset{\centerdot \centerdot }{\mathop{X}}\,e{{O}_{3}}\] (ii) \[\overset{\centerdot \centerdot }{\mathop{X}}\,eO{{F}_{4}}\]     (iii)  \[\overset{\centerdot \centerdot }{\mathop{X}}\,e{{F}_{6}}\] Those having same number of lone pairs on \[Xe\] are:

A) (i) and (ii) only

B) (i) and (iii) only

C) (ii) and (iii) only

D) (i), (ii) and (iii)                        

Correct Answer: D

Solution :

\[XeO{{F}_{4}}\]. square planar {\[s{{p}^{3}}{{a}^{2}}\] hybridization)                       As shown above all the compounds have one lone pair.