A) 475 J
B) 450 J
C) 275 J
D) 250 J
Correct Answer: A
Solution :
Key Idea: Apply work-energy theorem. When a force acts upon a moving body, then the kinetic energy of the body increases and the increase is equal to the work done. This is work energy theorem. Work done \[\left[ {{\tan }^{-1}}\frac{{{n}_{2}}}{{{n}_{1}}} \right]\] Another definition of work done is force x displacement. \[\left[ {{\tan }^{-1}}\frac{{{n}_{1}}}{{{n}_{2}}} \right]\] \[\pi V/m\] where the subscripts f and i stand for final and initial. \[2V/m\] \[10V/m\] \[62V/m\] \[I\] \[f\alpha \sqrt{Z}\] Using the formula \[f\alpha {{Z}^{2}}\] we have \[f\alpha Z\] \[f\alpha {{Z}^{3/2}}\] \[\sigma \] \[\sigma \] \[{{\varepsilon }_{0}}\] \[\sigma /2{{\varepsilon }_{0}}V/m\]
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