A) \[Fdx={{K}_{f}}-\frac{1}{2}mv_{i}^{2}\]
B) \[F.dx={{K}_{f}}-\frac{1}{2}\times 10\times {{(10)}^{2}}\]
C) \[\Rightarrow \]
D) \[F.dx={{K}_{f}}-500\]
Correct Answer: C
Solution :
Key Idea: Force per unit area is the radiation pressure. When a surface intercepts electromagnetic radiation, a force and a pressure are exerted on the surface. As the surface is non-reflecting, so, it is completely absorbed and in such case the force is, \[\frac{\Delta V}{V}\alpha {{B}^{-2}}\] where I is intensity of light. A is area of surface and c is velocity of electromagnetic wave. The radiation pressure is the force per unit area i.e., \[\sin \omega t-\cos t\omega t\]
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