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AIIMS AIIMS Solved Paper-2005

  • question_answer
    Two concentric conducting thin spherical shells A and B having radii \[\therefore \] and \[=\text{ }potential\text{ }\times \text{ }charge\]\[=\frac{KZe}{r}(-e)=-\frac{KZ{{e}^{2}}}{r}\] are charged to \[E=KE+PE\], and -\[=\frac{1}{2}\frac{KZ{{e}^{2}}}{r}-\frac{KZ{{e}^{2}}}{r}\] \[=\frac{KZ{{e}^{2}}}{2r}\]. The electrical field along a line. (passing through the centre) is:

    A)

    B)

    C)

    D)

    Correct Answer: C

    Solution :

                    As charge on shell B is negative so, potential inside B is constant and negative. Also due to positive charge, potential inside A is positive and constant and greater than that of B. Therefore, as r increases potential decreases and as \[E=KE+PE\] is crossed, potential becomes negative. At the surface of shell B, it is more negative. This variation is represented in graph (c). Note: This problem is considered as wrong, because question asked is for field and graphs are given by potential.


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