A) \[{{i}_{E}}={{i}_{B}}+{{i}_{C}}\]
B) \[\Rightarrow \]
C) \[\Delta {{i}_{E}}=\Delta {{i}_{B}}+\Delta {{i}_{C}}\]
D) \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}-\Delta {{i}_{C}}}\]
Correct Answer: A
Solution :
Key Idea: Electrons are lighter in weight compared to protons. In a semiconductor, hole is equivalent to a positively charged particle which moves in a direction opposite to that of an electron. Since electrons are lighter in mass compared to positively charged particles they move easily in the semiconducting material. Hence, the mobility of holes in p-type semiconductor is less than mobility of electrons in n- type semiconductor, i.e., \[{{n}_{e}}>{{n}_{h}}\] Note: n-type semiconductor because of presence of excess electrons is more preferred compared to p-type semiconductor which has excess of holes.
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