AIIMS AIIMS Solved Paper-2002

  • question_answer
    Velocity of light is equal to:

    A) \[Y=3K(1-2\sigma )\]

    B) \[{{I}_{1}}\]                       

    C) \[{{I}_{2}}\]                                       

    D) \[\phi \]

    Correct Answer: A

    Solution :

                                                    The relation between speed of light (c), permittivity of free space \[\phi =(2\pi +1)\pi \,n=1,2,3,..............\] and permeability of free space \[=\frac{2\pi }{\lambda }\times \] is by definition \[\Rightarrow \] Alternative: We know that the value of constants \[=\frac{\lambda }{2\pi }\times (2n+1)\pi \] and \[=\frac{(2n+1)\lambda }{2}\] are \[E=\sigma {{T}^{4}}\] Tm \[E=\sigma {{T}^{4}}\] and \[\frac{E}{E}=-\frac{2Q}{Q}\]putting this value in option (a), we have \[\Rightarrow \] which is velocity of light.


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