A) \[1.3\times {{10}^{-20}}g\]
B) \[5.01\times {{10}^{-21}}g\]
C) \[3.72\times {{10}^{23}}g\]
D) \[1.4\times {{10}^{-21}}g\]
Correct Answer: D
Solution :
Molecular mass of \[{{C}_{66}}{{H}_{122}}\] is \[=(12\times 60+122\times 1)=842\] \[\Rightarrow \] Mass of \[6.023\times {{10}^{23}}\] molecules of \[{{C}_{60}}{{H}_{122}}=384\] Mass of 1 molecule \[=\frac{842}{6.023\times {{10}^{23}}}\] \[=1.4\times {{10}^{-21}}g\]
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