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AIIMS AIIMS Solved Paper-2002

  • question_answer
    The kinetic energy of two moles of \[{{N}_{2}}\] at \[{{27}^{o}}C\] is (\[(R=8.24\,J{{K}^{-1}}mo{{l}^{-1}})\]

    A)  \[5491.6\text{ }J\]      

    B)         \[6491.6\text{ }J\]         

    C)  \[7491.6\text{ }J\]     

    D)  \[8882.4\text{ }J\]

    Correct Answer: C

    Solution :

    \[KE=\frac{3}{2}nRT\] \[n=2,R=8.324J/Kmol\] \[T=27+273=300K\] \[\therefore \]  \[KE=\frac{3}{2}\times 2\times 8.324\times 300\] \[=7491.6J\]


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