A) 1.5
B) 2.5
C) 0.5
D) 5.5
Correct Answer: A
Solution :
Rutherford on the basis of Coulombs law calculated the number of particles scattered at different angles and found that the number of particles N scattered at angle 9 are related as follows \[\Delta {{i}_{C}}=0.96\times 7.2=6.91mA\] \[\Delta {{i}_{E}}=\Delta {{i}_{C}}+\Delta {{i}_{B}}\] \[\therefore \] \[\Delta {{i}_{B}}=\Delta {{i}_{E}}-\Delta {{i}_{C}}\] \[=7.2-6.91=0.29mA\] \[\frac{(2n+1)\lambda }{2}\] \[\frac{(n+1)\lambda }{2}\]
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