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AIIMS AIIMS Solved Paper-2002

  • question_answer
    An electric bulb marked 40 W and 200 V, is used in a circuit of supply voltage 100 V. Now, its power is:

    A)  10 W        

    B)                        20 W                    

    C)        40 W                                    

    D)  100 W

    Correct Answer: A

    Solution :

    Power of bulb is given by \[{{k}_{1}}\] Supply voltage is 100 V and actual voltage is 200V \[{{F}_{1}}=-{{k}_{1}}{{y}_{1}}\]   \[{{F}_{2}}=-{{k}_{2}}{{y}_{2}}\] \[{{k}_{2}}\]  \[{{k}_{1}}\] \[{{k}_{2}}{{F}_{1}}+{{k}_{1}}{{F}_{2}}=-{{k}_{1}}{{k}_{2}}({{y}_{1}}+{{y}_{2}})=-{{k}_{1}}{{k}_{2}}y\]  \[{{F}_{1}}={{F}_{2}}=F(say)\]


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