A) 54° C
B) 627 °C
C) 927° C
D) 327° C
Correct Answer: C
Solution :
Speed of sound is given by \[=\frac{2\pi }{\lambda }\times \] ?...(1) where \[\Rightarrow \] is ratio of specific heat, P is pressure and d is density. Also PV = RT where V is volume, R gas constant and T is temperature. \[=\frac{\lambda }{2\pi }\times (2n+1)\pi \] \[=\frac{(2n+1)\lambda }{2}\] \[\frac{E}{E}=-\frac{2Q}{Q}\] Putting this value in Eq. (1), we get \[\Rightarrow \] Given, \[E=-\frac{E}{2}\] \[3.9\Omega \] \[\therefore \] \[V=E-ir\] \[i=\frac{E}{R+r}\] \[\therefore \] \[V=E-\left( \frac{E}{R+r} \right)r\] \[E=2V,\,r=0.1\Omega ,R=3.9\Omega \]
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