AIIMS AIIMS Solved Paper-2002

  • question_answer
    The bulk modulus of a metal is \[{{10}^{10}}\,N/{{m}^{2}}\] and Poissons ratio 0.20. If average distance between the molecules is 3 \[=\frac{1}{2\pi }\sqrt{\frac{{{k}_{1}}{{k}_{2}}}{({{k}_{1}}+{{k}_{2}})m}}\]. then the interatomic force constant is:

    A)  5.4 N/m     

    B)                        75 N/m

    C)  7.5 N/m                              

    D)  30 N/m

    Correct Answer: A

    Solution :

    The relation between bulk modulus K, Poissons ratio \[\tau \] and Youngs modulus Y is \[{{w}_{m}}=\frac{1}{10}{{\left( \frac{6400}{3200} \right)}^{2}}\times 200N\] Given, \[{{w}_{m}}=\frac{1}{10}\times 4\times 200=80N\] \[{{T}^{2}}=k{{R}^{3}}\]   \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3/2}}={{\left( \frac{1.01R}{R} \right)}^{3/2}}\] \[\Rightarrow \] Interatomic force constant is \[\frac{{{T}_{2}}}{{{T}_{1}}}={{(1+0.01)}^{3/2}}=1+\frac{3}{2}\times 0.01\] \[\frac{\Delta T}{T}\times 100=\left( \frac{{{T}_{2}}}{{{T}_{1}}}-1 \right)\times 100\]


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