A) 80 N
B) 40 N
C) 20 N
D) 8 N
Correct Answer: A
Solution :
According to the law of gravitation, the force of attraction acting on the body due to earth is given by \[{{I}_{1}}\] .....(1) Also from Newtons second law, we have \[{{I}_{2}}\] ?....(2) \[\phi \] \[I={{I}_{1}}+{{I}_{2}}+2\sqrt{{{I}_{1}}{{I}_{2}}}\cos \phi \] ?....(3) \[\cos \phi =-1\] where \[\phi =\pi ,3\pi ,5\pi ,.................\] are gravity on earth and moon respectively. Also \[\phi =(2\pi +1)\pi \,n=1,2,3,..............\] and \[=\frac{2\pi }{\lambda }\times \] are masses of moon and earth, and \[\Rightarrow \] and \[=\frac{\lambda }{2\pi }\times (2n+1)\pi \] their radil. Given, \[=\frac{(2n+1)\lambda }{2}\] \[E=\sigma {{T}^{4}}\] \[\sigma \] \[\frac{E}{E}=-\frac{2Q}{Q}\] \[\Rightarrow \]
You need to login to perform this action.
You will be redirected in
3 sec
