question_answer

A ray of light is incident on the surface of plate of glass of refractive index 1.5 at the polarizing angle. The angle of refraction of the ray will be:

A)  33.7°   

B)                                                        43.7°                    

C)  23.7°                                    

D)  53.7°

Correct Answer: A

Solution :

                From Brewsters law the relation between polarizing angle \[V=E-ir\] and refractive index n is \[i=\frac{E}{R+r}\] Given, n = 1.5 \[\therefore \]     \[V=E-\left( \frac{E}{R+r} \right)r\]  \[E=2V,\,r=0.1\Omega ,R=3.9\Omega \] For r as angle of refraction                 \[V=2-\left( \frac{2}{3.9+0.1} \right)\times 0.1\] \[V=1.95V\] \[{{m}_{1}}{{u}_{1}}={{m}_{2}}{{v}_{2}}\]