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AIIMS AIIMS Solved Paper-2002

  • question_answer
    If the vectors \[\vec{P}=a\hat{i}+a\hat{j}+3\hat{k}\] and \[=\frac{(2n+1)\lambda }{2}\]are perpendicular to each other then the positive value of a is:

    A)  zero                     

    B)        1                                            

    C)  2                                            

    D)  3

    Correct Answer: D

    Solution :

                    The scalar praduct of two vectors is given by \[\alpha =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{g}}}\] where \[\Delta {{i}_{C}}\] is angle between them. Given, \[\Delta {{i}_{g}}\] \[\alpha =0.96,\Delta {{i}_{E}}=7.2,\] \[\Delta {{i}_{C}}=0.96\times 7.2=6.91mA\]   \[\Delta {{i}_{E}}=\Delta {{i}_{C}}+\Delta {{i}_{B}}\] \[\therefore \] \[\Delta {{i}_{B}}=\Delta {{i}_{E}}-\Delta {{i}_{C}}\] \[=7.2-6.91=0.29mA\]   \[\frac{(2n+1)\lambda }{2}\] Hence, positive value of a is 3.


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